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51单片机里面的MD5加密算法

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发表于 2016-10-14 15:00:51 | 只看该作者 回帖奖励 |正序浏览 |阅读模式
本帖最后由 李维强-15级 于 2016-10-14 15:02 编辑

因为网上流传的MD5加密 C语言版 原封不动的移植到单片机上面就会出错,因为电脑上面都是32位系统,51上面是8位的,32上也是16位的吧,反正要出错,我花了点时间,模仿人家的算法,重新写了个MD5,就可以在单片机里面使用了
下面贴出源代码

md5.h
[C] syntaxhighlighter_viewsource syntaxhighlighter_copycode
#ifndef MD5_H  
#define MD5_H  
	 
typedef struct  
{  
		unsigned long count[2];  
		unsigned long state[4];  
		unsigned char buffer[64];     
}MD5_CTX;  
	 
													 
#define F(x,y,z) ((x & y) | (~x & z))  
#define G(x,y,z) ((x & z) | (y & ~z))  
#define H(x,y,z) (x^y^z)  
#define I(x,y,z) (y ^ (x | ~z))  
#define ROTATE_LEFT(x,n) ((x << n) | (x >> (32-n)))  
#define FF(a,b,c,d,x,s,ac) {a += F(b,c,d) + x + ac;a = ROTATE_LEFT(a,s);a += b;}  
#define GG(a,b,c,d,x,s,ac) {a += G(b,c,d) + x + ac;a = ROTATE_LEFT(a,s);a += b;}   
#define HH(a,b,c,d,x,s,ac) {a += H(b,c,d) + x + ac;a = ROTATE_LEFT(a,s);a += b;}  
#define II(a,b,c,d,x,s,ac) {a += I(b,c,d) + x + ac;a = ROTATE_LEFT(a,s);a += b;}                                           
void MD5Init(MD5_CTX *context);  
void MD5Update(MD5_CTX *context,unsigned char *input,unsigned long inputlen);  
void MD5Final(MD5_CTX *context,unsigned char digest[16]);  
void MD5Transform(unsigned long state[4],unsigned char block[64]);  
void MD5Encode(unsigned char *output,unsigned long *input,unsigned long len);  
void MD5Decode(unsigned long *output,unsigned char *input,unsigned long len);  
	 
#endif  


md5.c
[C] syntaxhighlighter_viewsource syntaxhighlighter_copycode
#include <string.h>  
#include "md5.h"  
unsigned char PADDING[]={0x80,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,  
												 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,  
												 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,  
												 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};  
													 
void MD5Init(MD5_CTX *context)  
{  
		 context->count[0] = 0;  
		 context->count[1] = 0;  
		 context->state[0] = 0x67452301;  
		 context->state[1] = 0xEFCDAB89;  
		 context->state[2] = 0x98BADCFE;  
		 context->state[3] = 0x10325476;  
}  
void MD5Update(MD5_CTX *context,unsigned char *input,unsigned long inputlen)  
{  
		unsigned long i = 0,index = 0,partlen = 0;  
		index = (context->count[0] >> 3) & 0x3F;  
		partlen = 64 - index;  
		context->count[0] += inputlen << 3;  
		if(context->count[0] < (inputlen << 3))  
			 context->count[1]++;  
		context->count[1] += inputlen >> 29;  
			
		if(inputlen >= partlen)  
		{  
			 memcpy(&context->buffer[index],input,partlen);  
			 MD5Transform(context->state,context->buffer);  
			 for(i = partlen;i+64 <= inputlen;i+=64)  
					 MD5Transform(context->state,&input[i]);  
			 index = 0;          
		}    
		else  
		{  
				i = 0;  
		}  
		memcpy(&context->buffer[index],&input[i],inputlen-i);  
}  
void MD5Final(MD5_CTX *context,unsigned char digest[16])  
{  
		unsigned long index = 0,padlen = 0;  
		unsigned char bits[8];  
		index = (context->count[0] >> 3) & 0x3F;  
		padlen = (index < 56)?(56-index):(120-index);  
		MD5Encode(bits,context->count,8);  
		MD5Update(context,PADDING,padlen);  
		MD5Update(context,bits,8);  
		MD5Encode(digest,context->state,16);  
}  
void MD5Encode(unsigned char *output,unsigned long *input,unsigned long len)  
{  
		unsigned long i = 0,j = 0;  
		while(j < len)  
		{  
				 output[j] = input[i] & 0xFF;    
				 output[j+1] = (input[i] >> 8) & 0xFF;  
				 output[j+2] = (input[i] >> 16) & 0xFF;  
				 output[j+3] = (input[i] >> 24) & 0xFF;  
				 i++;  
				 j+=4;  
		}  
}  
void MD5Decode(unsigned long *output,unsigned char *input,unsigned long len)  
{  
		 unsigned long i = 0,j = 0;  
		 while(j < len)  
		 {  
					 output[i] = ((unsigned long)(input[j])) |  
											 ((unsigned long)(input[j+1]) << 8) |  
											 ((unsigned long)(input[j+2]) << 16) |  
											 ((unsigned long)(input[j+3]) << 24);  
					 i++;  
					 j+=4;   
		 }  
}  
void MD5Transform(unsigned long state[4],unsigned char block[64])  
{  
		 unsigned long a = state[0];  
		 unsigned long b = state[1];  
		 unsigned long c = state[2];  
		 unsigned long d = state[3];  
		 unsigned long x[64];  
		 MD5Decode(x,block,64);  
		 FF(a, b, c, d, x[ 0], 7, 0xd76aa478); /* 1 */  
     FF(d, a, b, c, x[ 1], 12, 0xe8c7b756); /* 2 */  
     FF(c, d, a, b, x[ 2], 17, 0x242070db); /* 3 */  
     FF(b, c, d, a, x[ 3], 22, 0xc1bdceee); /* 4 */  
     FF(a, b, c, d, x[ 4], 7, 0xf57c0faf); /* 5 */  
     FF(d, a, b, c, x[ 5], 12, 0x4787c62a); /* 6 */  
     FF(c, d, a, b, x[ 6], 17, 0xa8304613); /* 7 */  
     FF(b, c, d, a, x[ 7], 22, 0xfd469501); /* 8 */  
     FF(a, b, c, d, x[ 8], 7, 0x698098d8); /* 9 */  
     FF(d, a, b, c, x[ 9], 12, 0x8b44f7af); /* 10 */  
     FF(c, d, a, b, x[10], 17, 0xffff5bb1); /* 11 */  
     FF(b, c, d, a, x[11], 22, 0x895cd7be); /* 12 */  
     FF(a, b, c, d, x[12], 7, 0x6b901122); /* 13 */  
     FF(d, a, b, c, x[13], 12, 0xfd987193); /* 14 */  
     FF(c, d, a, b, x[14], 17, 0xa679438e); /* 15 */  
     FF(b, c, d, a, x[15], 22, 0x49b40821); /* 16 */  
       
     /* Round 2 */  
     GG(a, b, c, d, x[ 1], 5, 0xf61e2562); /* 17 */  
     GG(d, a, b, c, x[ 6], 9, 0xc040b340); /* 18 */  
     GG(c, d, a, b, x[11], 14, 0x265e5a51); /* 19 */  
     GG(b, c, d, a, x[ 0], 20, 0xe9b6c7aa); /* 20 */  
     GG(a, b, c, d, x[ 5], 5, 0xd62f105d); /* 21 */  
     GG(d, a, b, c, x[10], 9,  0x2441453); /* 22 */  
     GG(c, d, a, b, x[15], 14, 0xd8a1e681); /* 23 */  
     GG(b, c, d, a, x[ 4], 20, 0xe7d3fbc8); /* 24 */  
     GG(a, b, c, d, x[ 9], 5, 0x21e1cde6); /* 25 */  
     GG(d, a, b, c, x[14], 9, 0xc33707d6); /* 26 */  
     GG(c, d, a, b, x[ 3], 14, 0xf4d50d87); /* 27 */  
     GG(b, c, d, a, x[ 8], 20, 0x455a14ed); /* 28 */  
     GG(a, b, c, d, x[13], 5, 0xa9e3e905); /* 29 */  
     GG(d, a, b, c, x[ 2], 9, 0xfcefa3f8); /* 30 */  
     GG(c, d, a, b, x[ 7], 14, 0x676f02d9); /* 31 */  
     GG(b, c, d, a, x[12], 20, 0x8d2a4c8a); /* 32 */  
       
     /* Round 3 */  
     HH(a, b, c, d, x[ 5], 4, 0xfffa3942); /* 33 */  
     HH(d, a, b, c, x[ 8], 11, 0x8771f681); /* 34 */  
     HH(c, d, a, b, x[11], 16, 0x6d9d6122); /* 35 */  
     HH(b, c, d, a, x[14], 23, 0xfde5380c); /* 36 */  
     HH(a, b, c, d, x[ 1], 4, 0xa4beea44); /* 37 */  
     HH(d, a, b, c, x[ 4], 11, 0x4bdecfa9); /* 38 */  
     HH(c, d, a, b, x[ 7], 16, 0xf6bb4b60); /* 39 */  
     HH(b, c, d, a, x[10], 23, 0xbebfbc70); /* 40 */  
     HH(a, b, c, d, x[13], 4, 0x289b7ec6); /* 41 */  
     HH(d, a, b, c, x[ 0], 11, 0xeaa127fa); /* 42 */  
     HH(c, d, a, b, x[ 3], 16, 0xd4ef3085); /* 43 */  
     HH(b, c, d, a, x[ 6], 23,  0x4881d05); /* 44 */  
     HH(a, b, c, d, x[ 9], 4, 0xd9d4d039); /* 45 */  
     HH(d, a, b, c, x[12], 11, 0xe6db99e5); /* 46 */  
     HH(c, d, a, b, x[15], 16, 0x1fa27cf8); /* 47 */  
     HH(b, c, d, a, x[ 2], 23, 0xc4ac5665); /* 48 */  
       
     /* Round 4 */  
     II(a, b, c, d, x[ 0], 6, 0xf4292244); /* 49 */  
     II(d, a, b, c, x[ 7], 10, 0x432aff97); /* 50 */  
     II(c, d, a, b, x[14], 15, 0xab9423a7); /* 51 */  
     II(b, c, d, a, x[ 5], 21, 0xfc93a039); /* 52 */  
     II(a, b, c, d, x[12], 6, 0x655b59c3); /* 53 */  
     II(d, a, b, c, x[ 3], 10, 0x8f0ccc92); /* 54 */  
     II(c, d, a, b, x[10], 15, 0xffeff47d); /* 55 */  
     II(b, c, d, a, x[ 1], 21, 0x85845dd1); /* 56 */  
     II(a, b, c, d, x[ 8], 6, 0x6fa87e4f); /* 57 */  
     II(d, a, b, c, x[15], 10, 0xfe2ce6e0); /* 58 */  
     II(c, d, a, b, x[ 6], 15, 0xa3014314); /* 59 */  
     II(b, c, d, a, x[13], 21, 0x4e0811a1); /* 60 */  
     II(a, b, c, d, x[ 4], 6, 0xf7537e82); /* 61 */  
     II(d, a, b, c, x[11], 10, 0xbd3af235); /* 62 */  
     II(c, d, a, b, x[ 2], 15, 0x2ad7d2bb); /* 63 */  
     II(b, c, d, a, x[ 9], 21, 0xeb86d391); /* 64 */  
		 state[0] += a;  
		 state[1] += b;  
		 state[2] += c;  
		 state[3] += d;  
}  



main函数的调用过程
[C] syntaxhighlighter_viewsource syntaxhighlighter_copycode
#include <stdio.h>  
#include <stdlib.h>  
#include "md5.h"  
#include <string.h>

int main()  
{  
    int i;  
    unsigned char encrypt[] ="admin";//21232f297a57a5a743894a0e4a801fc3  
    unsigned char decrypt[16];      
    MD5_CTX md5;  
    MD5Init(&md5);                
    MD5Update(&md5,encrypt,strlen((char *)encrypt));  
    MD5Final(&md5,decrypt);          
    printf("加密前:%s\n加密后:",encrypt);  
    for(i=0;i<16;i++)  
    {  
        printf("%02x",decrypt[i]);  
    }  
      
    getchar();  
      
    return 0;  
}  
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发表于 2016-10-15 15:30:58 | 只看该作者
这个还是有问题,debug得行,到单片机里面就不得行了
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