51单片机里面的MD5加密算法
本帖最后由 李维强-15级 于 2016-10-14 15:02 编辑因为网上流传的MD5加密 C语言版 原封不动的移植到单片机上面就会出错，因为电脑上面都是32位系统，51上面是8位的，32上也是16位的吧，反正要出错，我花了点时间，模仿人家的算法，重新写了个MD5，就可以在单片机里面使用了
下面贴出源代码
md5.h
#ifndef MD5_H
#define MD5_H
typedef struct
{
unsigned long count;
unsigned long state;
unsigned char buffer;
}MD5_CTX;
#define F(x,y,z) ((x & y) | (~x & z))
#define G(x,y,z) ((x & z) | (y & ~z))
#define H(x,y,z) (x^y^z)
#define I(x,y,z) (y ^ (x | ~z))
#define ROTATE_LEFT(x,n) ((x << n) | (x >> (32-n)))
#define FF(a,b,c,d,x,s,ac) {a += F(b,c,d) + x + ac;a = ROTATE_LEFT(a,s);a += b;}
#define GG(a,b,c,d,x,s,ac) {a += G(b,c,d) + x + ac;a = ROTATE_LEFT(a,s);a += b;}
#define HH(a,b,c,d,x,s,ac) {a += H(b,c,d) + x + ac;a = ROTATE_LEFT(a,s);a += b;}
#define II(a,b,c,d,x,s,ac) {a += I(b,c,d) + x + ac;a = ROTATE_LEFT(a,s);a += b;}
void MD5Init(MD5_CTX *context);
void MD5Update(MD5_CTX *context,unsigned char *input,unsigned long inputlen);
void MD5Final(MD5_CTX *context,unsigned char digest);
void MD5Transform(unsigned long state,unsigned char block);
void MD5Encode(unsigned char *output,unsigned long *input,unsigned long len);
void MD5Decode(unsigned long *output,unsigned char *input,unsigned long len);
#endif
md5.c
#include <string.h>
#include "md5.h"
unsigned char PADDING[]={0x80,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};
void MD5Init(MD5_CTX *context)
{
context->count = 0;
context->count = 0;
context->state = 0x67452301;
context->state = 0xEFCDAB89;
context->state = 0x98BADCFE;
context->state = 0x10325476;
}
void MD5Update(MD5_CTX *context,unsigned char *input,unsigned long inputlen)
{
unsigned long i = 0,index = 0,partlen = 0;
index = (context->count >> 3) & 0x3F;
partlen = 64 - index;
context->count += inputlen << 3;
if(context->count < (inputlen << 3))
context->count++;
context->count += inputlen >> 29;
if(inputlen >= partlen)
{
memcpy(&context->buffer,input,partlen);
MD5Transform(context->state,context->buffer);
for(i = partlen;i+64 <= inputlen;i+=64)
MD5Transform(context->state,&input);
index = 0;
}
else
{
i = 0;
}
memcpy(&context->buffer,&input,inputlen-i);
}
void MD5Final(MD5_CTX *context,unsigned char digest)
{
unsigned long index = 0,padlen = 0;
unsigned char bits;
index = (context->count >> 3) & 0x3F;
padlen = (index < 56)?(56-index):(120-index);
MD5Encode(bits,context->count,8);
MD5Update(context,PADDING,padlen);
MD5Update(context,bits,8);
MD5Encode(digest,context->state,16);
}
void MD5Encode(unsigned char *output,unsigned long *input,unsigned long len)
{
unsigned long i = 0,j = 0;
while(j < len)
{
output = input & 0xFF;
output = (input >> 8) & 0xFF;
output = (input >> 16) & 0xFF;
output = (input >> 24) & 0xFF;
i++;
j+=4;
}
}
void MD5Decode(unsigned long *output,unsigned char *input,unsigned long len)
{
unsigned long i = 0,j = 0;
while(j < len)
{
output = ((unsigned long)(input)) |
((unsigned long)(input) << 8) |
((unsigned long)(input) << 16) |
((unsigned long)(input) << 24);
i++;
j+=4;
}
}
void MD5Transform(unsigned long state,unsigned char block)
{
unsigned long a = state;
unsigned long b = state;
unsigned long c = state;
unsigned long d = state;
unsigned long x;
MD5Decode(x,block,64);
FF(a, b, c, d, x[ 0], 7, 0xd76aa478); /* 1 */
FF(d, a, b, c, x[ 1], 12, 0xe8c7b756); /* 2 */
FF(c, d, a, b, x[ 2], 17, 0x242070db); /* 3 */
FF(b, c, d, a, x[ 3], 22, 0xc1bdceee); /* 4 */
FF(a, b, c, d, x[ 4], 7, 0xf57c0faf); /* 5 */
FF(d, a, b, c, x[ 5], 12, 0x4787c62a); /* 6 */
FF(c, d, a, b, x[ 6], 17, 0xa8304613); /* 7 */
FF(b, c, d, a, x[ 7], 22, 0xfd469501); /* 8 */
FF(a, b, c, d, x[ 8], 7, 0x698098d8); /* 9 */
FF(d, a, b, c, x[ 9], 12, 0x8b44f7af); /* 10 */
FF(c, d, a, b, x, 17, 0xffff5bb1); /* 11 */
FF(b, c, d, a, x, 22, 0x895cd7be); /* 12 */
FF(a, b, c, d, x, 7, 0x6b901122); /* 13 */
FF(d, a, b, c, x, 12, 0xfd987193); /* 14 */
FF(c, d, a, b, x, 17, 0xa679438e); /* 15 */
FF(b, c, d, a, x, 22, 0x49b40821); /* 16 */
/* Round 2 */
GG(a, b, c, d, x[ 1], 5, 0xf61e2562); /* 17 */
GG(d, a, b, c, x[ 6], 9, 0xc040b340); /* 18 */
GG(c, d, a, b, x, 14, 0x265e5a51); /* 19 */
GG(b, c, d, a, x[ 0], 20, 0xe9b6c7aa); /* 20 */
GG(a, b, c, d, x[ 5], 5, 0xd62f105d); /* 21 */
GG(d, a, b, c, x, 9,0x2441453); /* 22 */
GG(c, d, a, b, x, 14, 0xd8a1e681); /* 23 */
GG(b, c, d, a, x[ 4], 20, 0xe7d3fbc8); /* 24 */
GG(a, b, c, d, x[ 9], 5, 0x21e1cde6); /* 25 */
GG(d, a, b, c, x, 9, 0xc33707d6); /* 26 */
GG(c, d, a, b, x[ 3], 14, 0xf4d50d87); /* 27 */
GG(b, c, d, a, x[ 8], 20, 0x455a14ed); /* 28 */
GG(a, b, c, d, x, 5, 0xa9e3e905); /* 29 */
GG(d, a, b, c, x[ 2], 9, 0xfcefa3f8); /* 30 */
GG(c, d, a, b, x[ 7], 14, 0x676f02d9); /* 31 */
GG(b, c, d, a, x, 20, 0x8d2a4c8a); /* 32 */
/* Round 3 */
HH(a, b, c, d, x[ 5], 4, 0xfffa3942); /* 33 */
HH(d, a, b, c, x[ 8], 11, 0x8771f681); /* 34 */
HH(c, d, a, b, x, 16, 0x6d9d6122); /* 35 */
HH(b, c, d, a, x, 23, 0xfde5380c); /* 36 */
HH(a, b, c, d, x[ 1], 4, 0xa4beea44); /* 37 */
HH(d, a, b, c, x[ 4], 11, 0x4bdecfa9); /* 38 */
HH(c, d, a, b, x[ 7], 16, 0xf6bb4b60); /* 39 */
HH(b, c, d, a, x, 23, 0xbebfbc70); /* 40 */
HH(a, b, c, d, x, 4, 0x289b7ec6); /* 41 */
HH(d, a, b, c, x[ 0], 11, 0xeaa127fa); /* 42 */
HH(c, d, a, b, x[ 3], 16, 0xd4ef3085); /* 43 */
HH(b, c, d, a, x[ 6], 23,0x4881d05); /* 44 */
HH(a, b, c, d, x[ 9], 4, 0xd9d4d039); /* 45 */
HH(d, a, b, c, x, 11, 0xe6db99e5); /* 46 */
HH(c, d, a, b, x, 16, 0x1fa27cf8); /* 47 */
HH(b, c, d, a, x[ 2], 23, 0xc4ac5665); /* 48 */
/* Round 4 */
II(a, b, c, d, x[ 0], 6, 0xf4292244); /* 49 */
II(d, a, b, c, x[ 7], 10, 0x432aff97); /* 50 */
II(c, d, a, b, x, 15, 0xab9423a7); /* 51 */
II(b, c, d, a, x[ 5], 21, 0xfc93a039); /* 52 */
II(a, b, c, d, x, 6, 0x655b59c3); /* 53 */
II(d, a, b, c, x[ 3], 10, 0x8f0ccc92); /* 54 */
II(c, d, a, b, x, 15, 0xffeff47d); /* 55 */
II(b, c, d, a, x[ 1], 21, 0x85845dd1); /* 56 */
II(a, b, c, d, x[ 8], 6, 0x6fa87e4f); /* 57 */
II(d, a, b, c, x, 10, 0xfe2ce6e0); /* 58 */
II(c, d, a, b, x[ 6], 15, 0xa3014314); /* 59 */
II(b, c, d, a, x, 21, 0x4e0811a1); /* 60 */
II(a, b, c, d, x[ 4], 6, 0xf7537e82); /* 61 */
II(d, a, b, c, x, 10, 0xbd3af235); /* 62 */
II(c, d, a, b, x[ 2], 15, 0x2ad7d2bb); /* 63 */
II(b, c, d, a, x[ 9], 21, 0xeb86d391); /* 64 */
state += a;
state += b;
state += c;
state += d;
}
main函数的调用过程
#include <stdio.h>
#include <stdlib.h>
#include "md5.h"
#include <string.h>
int main()
{
int i;
unsigned char encrypt[] ="admin";//21232f297a57a5a743894a0e4a801fc3
unsigned char decrypt;
MD5_CTX md5;
MD5Init(&md5);
MD5Update(&md5,encrypt,strlen((char *)encrypt));
MD5Final(&md5,decrypt);
printf("加密前:%s\n加密后:",encrypt);
for(i=0;i<16;i++)
{
printf("%02x",decrypt);
}
getchar();
return 0;
} 这个还是有问题，debug得行，到单片机里面就不得行了
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